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Q.

Which of the following values of α satisfy the equation1+α21+2α21+3α22+α22+2α22+3α23+α23+2α23+3α2=−648α

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a

9

b

-4

c

-9

d

9

answer is C.

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Detailed Solution

1+α21+2α21+3α22+α22+2α22+3α23+α23+2α23+3α2=−648α                                                      •R2→R2−R1,.R3→R3−R21+α21+2α21+323+2α3+4α3+6α5+2α5+4α5+6α=−648α                                                        •R3→R3−R21+α21+2α21+3α23+2α3+4α3+6α222=−648α1+α21+2α21+3α23+2α3+4α3+6α111=−324α                                                    •C2→C2-C1 ; C3→C3−C21+α22α+3α22α+5α23+2α2α2α100=−324α                                                    •C3→C3−C21+α22+3αα2α23+2α2α0100=−324α2α−2α2=−324α⇒α2=−324−4=81⇒α=±9
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