Q.
Which of the following is wrong?
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a
p∨~p a tautology
b
~(~p)↔p is a tautology
c
p∧~p is a contradiction
d
((p∧q)→q)→p is a tautology
answer is D.
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Detailed Solution
The truth value of ~(~p)↔pa p as followSince, last column of above truth table contains only T. Hence, ~(~p)→p is a tautology.
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