Which if the following statements are wrongS-I:Ltx→0e1x-e-1xe1x+e-1x does not exist e1x-e-1xe1x+e-1xS-II: If a∈R and f(x)=xae1x-e-1xe1x+e-1x,  x≠00,x=0is continuous  And differentiable ∀x∈R then a>1

Ltx→0+   1−e−2x1+e−2x=1−01+0=1   ,  Ltx→0−  e−2x−1e−2x+1=0−10+1=−1∴  S - I does not existsf(x) is a continuous at x=0 ∴ f(0)=lim x→0f(x)=lim x→0xae1x-e-1xe1x+e-1x⇒a>0 At x=0  f(x) is differentiable ⇒limx→0f(x)-f(0)x-0 exists ⇒Lx→0xa-1e1x-e-1xe1x+e-1x   exists ⇒a-1>0⇒a>1