Download the app

Questions  

which pair of functions is identical?

a
sin−1⁡(sin⁡x) and sin⁡sin−1⁡x
b
loge⁡ex,eloge⁡x
c
loge⁡x2,2loge⁡x
d
None of these

detailed solution

Correct option is D

Here, (a) sin−1⁡(sin⁡x) is defined for x∈−π2,π2, while sin⁡sin−1⁡x is defined only for x∈[−1,1] (b) loge⁡ex, is defined for all x, while eloge⁡x is defined for x>0.  (c) loge⁡x2 is defined for all x∈R−{0}, while 2loge⁡x is definedforx>0. Thus, none is identical.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Letfx=a2-5a+4x3-6a2-5a+1x-tanx(sgnx) be an even function for all xR. Then the sum of all possible values of a is (where [.] and {.} denote greatest integer function and fractional part function, respectively)


phone icon
whats app icon