Q.
which pair of functions is identical?
see full answer
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a
sin−1(sinx) and sinsin−1x
b
logeex,elogex
c
logex2,2logex
d
None of these
answer is D.
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Detailed Solution
Here, (a) sin−1(sinx) is defined for x∈−π2,π2, while sinsin−1x is defined only for x∈[−1,1] (b) logeex, is defined for all x, while elogex is defined for x>0. (c) logex2 is defined for all x∈R−{0}, while 2logex is definedforx>0. Thus, none is identical.
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