which pair of functions is identical?
sin−1(sinx) and sinsin−1x
logeex,elogex
logex2,2logex
None of these
Here, (a) sin−1(sinx) is defined for x∈−π2,π2, while sinsin−1x is defined only for x∈[−1,1]
(b) logeex, is defined for all x, while elogex is defined for x>0.
(c) logex2 is defined for all x∈R−{0}, while 2logex is definedforx>0.
Thus, none is identical.