Q.
Which term is greatest (Numerically) in the expansion 1+3x515 when x=13
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answer is 3.
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Detailed Solution
We have n=15;X=3x5=35·13∵x=13=15 Now (n+1)|X||X|+1=(15+1)×1515+1=16×1565=186=2.6=2+0.6=p+F∴ Numerically greatest term is Tp+1=T2+1=T3
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