Questions
Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability that
both B's are not together and both .I's are not together is
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Correct option is B
The total number of cases is 11!/2!×2!. Thenumberof favorable cases is [11!/(2!×2!)]−9! Therefore, the required probability is 1−9!×411!=5355Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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