Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability thatboth B's are not together and both .I's are not together is
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a
5255
b
5355
c
5455
d
None of these
answer is B.
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Detailed Solution
The total number of cases is 11!/2!×2!. Thenumberof favorable cases is [11!/(2!×2!)]−9! Therefore, the required probability is 1−9!×411!=5355
Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability thatboth B's are not together and both .I's are not together is