Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability thatboth B's are not together and both .I's are not together is

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5255

5355

5455

None of these

answer is B.

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Detailed Solution

The total number of cases is 11!/2!×2!. Thenumberof favorable cases is [11!/(2!×2!)]−9! Therefore, the required probability is 1−9!×411!=5355

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