Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability that both .B's are not together and both I's are not together is
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a
5255
b
5355
c
5455
d
none of these
answer is B.
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Detailed Solution
The total number of cases is 11!(2! x 2!). The number of favorable cases is [11!(2! x 2!)] - 9! Therefore, the required probability is=1−9!×411!=5355
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Words from the letters of the word PROBABILITY are formed by taking all letters at a time. The probability that both .B's are not together and both I's are not together is