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$x \cos x \frac{d y}{d x} + y (x \sin x + \cos x) = 1 then xy =$

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detailed solution

Correct option is A

dydx+xsin⁡x+cos⁡xxcos⁡xy=1xcos⁡x I.F =exp⁡∫xsin⁡x+cos⁡xxcos⁡xdxexp⁡∫tan⁡x+1xdx=x⋅sec⁡x Solution is y⋅xsec⁡x=∫x⋅sec⁡xxcos⁡x=tan⁡x+c∴xy=sin⁡x+c⋅cos⁡x

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xcos⁡xdydx+y(xsin⁡x+cos⁡x)=1 then xy=

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$x \cos x \frac{d y}{d x} + y (x \sin x + \cos x) = 1 then xy =$