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$x = \cot 6 ° \cot 42 °, y = \tan 66 ° \tan 78 °$ then $\frac{y}{x} =$

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Correct option is B

x=cot6°cot42°, y=tan66°tan78°yx=tan6°tan42°tan66°tan78° =tan6°tan54°tan66°tan18°tan42°tan78°tan54°tan18° =tan18°tan54°tan54°tan18° ∵tanθtan60∘-θan60∘+θ=tan3θ =1

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x=cot6°cot42°, y=tan66°tan78° thenyx=

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$x = \cot 6 ° \cot 42 °, y = \tan 66 ° \tan 78 °$ then $\frac{y}{x} =$