Equation of line in Straight lines

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The x- intercept of the line joining the points $(3, 1)$ and $(1, 3)$ is

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Solution

Equation of the line joining the points $P (x_{1}, y_{1})$ and $Q (x_{2}, y_{2})$ is $y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{2}} (x - x_{1})$
Hence the equation of the line joining the points $(3, 1)$ and $(1, 3)$ is $y - 1 = \frac{3 - 1}{1 - 3} (x - 3)$
To get x- intercept, substitute $x = a, y = 0$ in the above equation
$\begin{matrix} 0 - 1 = - 1 (a - 3) \\ a = 3 + 1 \\ = 4 \end{matrix}$
Therefore, x-the intercept is $4$

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Equation of line in Straight lines

Remember concepts with our Masterclasses.

The x- intercept of the line joining the points 3,1 and 1,3 is

Equation of the line joining the points Px1,y1 and Qx2,y2 is y−y1=y2−y1x2−x2x−x1Hence the equation of the line joining the points 3,1 and 1,3 is y−1=3−11−3x−3To get x- intercept, substitute x=a,y=0 in the above equation 0−1=−1a−3a=3+1=4 Therefore, x-the intercept is 4

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The x- intercept of the line joining the points $(3, 1)$ and $(1, 3)$ is