xlog5⁡x>5 implies

xlog5⁡x>5Taking logarithm with base 5, we have     log5⁡xlog5⁡x>1 or     log5⁡x−1log5⁡x+1>0 or     log5⁡x>1 or log5⁡x<−1⇒    x>5 or x<1/5Also we must have x > 0. Thus, x∈(0,1/5)∪(5,∞)