x=∑n=0∞ cos2nθ,y=∑n=0∞ sin2nθ,z=∑n=0∞ cos2nθsin2nθ|cosθ|<1, |sinθ|<1 then x+y+z is equal to
xy
yz
zx
xyz
x=11−cos2x=1sin2x,y=1cos2x and z=11−sin2xcos2x=11−1x⋅1y=xyxy−1⇒z(xy−1)=xy=x+y⇒x+y+z=xyz.