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$x = \sin | \sin θ | y = \cos θ | \cos θ |$ where $\frac{99 π}{2} \leq θ \leq 50 π$ , then

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Correct option is D

If 99π2≤θ≤50π⇒3π2≤θ≤2π⇒x=-sin2θ and y=cos2θ⇒y-x=1

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x=sin|sinθ| y=cosθ|cosθ| where99π2≤θ≤50π, then

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$x = \sin | \sin θ | y = \cos θ | \cos θ |$ where $\frac{99 π}{2} \leq θ \leq 50 π$ , then