First slide

Introduction to limits

Question

$For x \in (- δ, δ), where δ is positive and δ \to 0, [\lim_{x \to 0} \frac{\sin x}{x}] is equal to$

Moderate

A

1
B

0
C

2
D

3

Solution

$\begin{array}{l} For small values of x, we know that s i n x < x \\ \lim_{x \to 0} \frac{\sin x}{x} = 1^{-} \Rightarrow [\lim_{x \to 0} \frac{\sin x}{x}] = 0 \end{array}$

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