First slide
Introduction to P.M.I
Question

xxn1n1+αn(n1) is divisible by  (xα)2 for

Moderate
Solution

Let P(n)=xxn1n1+αn(n1)=(xα)2g(x)
P(1)00istrue.
Let xxk1k1+αk(k1)=(xα)2g(x)P(k+1)xxk(k+1)αk+αk+1(k)(xα)2xg(x)+k1
So, holds for all nN 

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