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x = y cos(4π3)=zcos(8π3)then xy + yz + zx =

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a

1

b

-1

c

12

d

0

answer is D.

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Detailed Solution

x=ycos(4π3)=zcos(8π3)⇒x=−y2=−z2=kxy+yz+zx=k(−2k)+(−2k)(−2k)+(−2k)k=0

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