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Q.

x=1−y1+y⇒dydx =

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a

4x+12

b

4x−11+x3

c

x−11+x3

d

4x+13

answer is B.

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Detailed Solution

x=1−y1+y⇒1+x1−x=1+y+1−y1+y−1+y=1y⇒y=1−x1+x2dydx=21−x1+x×1+x−1−1−x11+x2=21−x1+x3−1−x−1+x=4x−11+x3
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