x,y,z are natural numbers, not greater than 6. How many ordered triples (x,y,z) are  there such that the product xyz is divisible by 10 ?

Total 63=21653=125 product do not have 5 as a factor  (1,2,3,4,6)33=27 product do not have 2 as a factor (1,3,5)23=8 product do not have 2 \& 5 as factors (1,3)∴216−125−27+8=72