$\frac{1}{x}+\frac{2}{y}+\frac{1}{z}=2,$ $\frac{3}{x}-\frac{4}{y}-\frac{2}{z}=1,$ and $\frac{2}{x}+\frac{5}{y}-\frac{2}{z}=3,$

Then the value of $y$  is___________.

$D=\left|\begin{array}{ccc}1& 2& 1\\ 3& -4& -2\\ 2& 5& -2\end{array}\right|=45,$               $D_{1/x}=3\left|\begin{array}{ccc}1& 2& 1\\ 2& -4& -2\\ 2& 5& -2\end{array}\right|=36,$ 

$D_{1/y}=3\left|\begin{array}{ccc}1& 1& 1\\ 3& 2& -2\\ 2& 3& -2\end{array}\right|=9,$             $D_{1/z}=3\left|\begin{array}{ccc}1& 2& 1\\ 3& -4& 2\\ 2& 5& -3\end{array}\right|=-9$

$x=\frac{5}{4},y=5,z=-5$

Hence value of $y$  is $5.$