y=mx+c c is a normal to the ellipsex2/a2+y2/b2=1 if c2 is equal to
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a
a2−b22a2m2+b2
b
a2−b22a2m2
c
a2−b22m2a2+b2m2
d
a2−b22m2a2m2+b2
answer is C.
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Detailed Solution
Equation of a normal to the ellipse x2/a2+y2/b2=1 is axcosθ−bysinθ=a2−b2 , if it represents mx−y=−c then amcosθ=bsinθ=−a2−b2c⇒ cosθ=acma2−b2,sinθ=−bca2−b2⇒ c2a2−b22a2m2+b2=1⇒ a2−b22m2a2+b2m2