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Questions  

y=mx+c c is a normal to the ellipse

x2/a2+y2/b2=1 if  c2  is equal to 

a
a2−b22a2m2+b2
b
a2−b22a2m2
c
a2−b22m2a2+b2m2
d
a2−b22m2a2m2+b2

detailed solution

Correct option is C

Equation of a normal to the ellipse x2/a2+y2/b2=1 is axcos⁡θ−bysin⁡θ=a2−b2  , if it represents mx−y=−c then amcos⁡θ=bsin⁡θ=−a2−b2c⇒ cos⁡θ=acma2−b2,sin⁡θ=−bca2−b2⇒ c2a2−b22a2m2+b2=1⇒ a2−b22m2a2+b2m2

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