A young couple has two children. The probability that both children are boys, if it is known that atleast one of the children is a boy is
14
13
110
120
n(A) = 2C1+ 2C2→ both boys ↓ Only one boy
n(A∩B) = 2C2
P(B/A) = n(A∩B)n(A) = 12+1 = 13