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Q.

Az1,Bz2,Cz3&Dz4  are four points in complex plane where z1,z2,z3&z4 are roots of the equation z4+z3+2z2+z+1=0  then

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a

ABCD is rectangle

b

ABCD is cyclic

c

z1=z2=z3=z4=1

d

z14+z24+z34+z44 is purely imaginary

answer is B.

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Detailed Solution

z2+1 2+zz2+1=0  ⇒z2+1z2+z+1=0 roots are i,-i,ω&ω2 magnitudes are equal for all the above complex numbers and each  is equal to 1, and they are concyclic
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Az1,Bz2,Cz3&Dz4  are four points in complex plane where z1,z2,z3&z4 are roots of the equation z4+z3+2z2+z+1=0  then