A→ and B→ are two vectors and θ is the angle between then, if |A→×B→|=3(A→.B→) , the value of θ is

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450

300

900

600

answer is D.

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Detailed Solution

Given ; |A→×B→|=3(A→.B→) or ABsinθ=3ABcosθ or tanθ=3=tan600,θ=600

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