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μ=A+Bλ+Cλ2 is dimensionally correct the dimensions of A,B&C respectively are (μ,A,B,C are constants where λ is wave length and μ is refractive index)

a
No Dimensions,L,  L2
b
L2,No Dimensions,  L
c
L, L2,No Dimensions
d
L,No dimensions,L2

detailed solution

Correct option is A

given μ=A+Bλ+Cλ2​Refractive index μ=sinisinr=M0L0T0;   λ   is wave length =LAccording to principle of homogeneity​dimensions of A=μ=no dimensions​​Bλ=μ⇒ B=μλ⇒B=L Cλ2=μ⇒ C=μλ2 ⇒C=L2

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