μ=A+Bλ+Cλ2 is dimensionally correct the dimensions of A,B & C respectively are (μ,A,B,C are constants where λ is wave length and μ is refractive index)
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a
No Dimensions,L, L2
b
L2,No Dimensions, L
c
L, L2,No Dimensions
d
L,No dimensions,L2
answer is A.
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Detailed Solution
given μ=A+Bλ+Cλ2Refractive index μ=sinisinr=M0L0T0; λ is wave length =LAccording to principle of homogeneitydimensions of A=μ=no dimensionsBλ=μ⇒ B=μλ⇒B=L Cλ2=μ⇒ C=μλ2 ⇒C=L2