A body of mass 5kg has linear momentum of 20kgm/s. If a constant force of 4N acts on it in the direction of its motion for 10s. The change in kinetic energy of the body is

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400 J

600 J

200 J

320 J

answer is D.

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Detailed Solution

F×t=pf−pe 4×10=pf−20⇒pf=60 ΔKE=12m(pf2−pi2)=12×5(602−202) = 320 J