Questions
A body is projected making an angle of 600 with horizontal from the base of an inclined plane having an inclination of 300 with horizontal. When the same body is projected vertically upward with same speed, maximum height attained by it is 45 m. Then its range on the inclined plane is
a
b
80 5\sqrt{3} m
c
d
detailed solution
Correct option is B
u2 sin26002×10 = 45 ⇒u2 =1200 m2/s2 Therefore range on inclined plane = 2u2 sin (α-β)g cos2β = 2×1200×sin 30010×cos2300 m =80 mTalk to our academic expert!
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