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−20 μC, 40 μC and q are the charges on three identical spherical conductors P, Q and R respectively. Now P and Q attract each other with a force F when they are separated by a distance d. Now P and Q are made in contact with each other and then separated. Again Q and R are touched and they are separated by a distance ‘d’. The repulsive force between Q and R is 2F. Then the charge q is

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a

10μC

b

30μC

c

40μC

d

70 μC

answer is D.

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Detailed Solution

During conduction, due to contact each sphere acquires average of both the charges. F =14π∈0q1q2d2q1=-20μC=-20×10-6 C and q2=40μC =40×10-6 CF=9×109×20×40×10−12d2---(1)when P, Q are touched and separted they get each of charge =-20+402=10μC2F=9×109×(10+q2)2d2----(2)Form (1) and (2) we get ⇒q=70 μc

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