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Q.

1 μC charge is shifted from A to B and it is found that work done by an external force is 40 μJ in doing so against electrostatic forces then, find the magnitude of potential difference VB−VA (in volts).

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answer is 40.

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Detailed Solution

The potential difference between two points in electric fieldVB−VA=Wext(A→B)q=40×10−61×10−6=40V

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