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Q.

A coil has an inductance of 0.7H and is joined in series with a resistance of 220Ω . When an alternating e.m.f. of 220V at 50cps. Is applied to it, then the wattles component of the current in the circuit is

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a

5A

b

0.5A

c

0.7A

d

7A

answer is B.

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Detailed Solution

Wattles component of ac =Ivsinθ=EvZsinθ =220R2+L2ω2×LωR2+L2ω2 ∴Lω=0.7×2π×50 =220×Lω(R2+L2ω2)=0.7×2×227×50 =220×(0.7×2π×50)(2202+2202)=220Ω I=220×2202202(2)=12=0.5A
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