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$\int \frac{dx}{\sqrt{2 ax - x^{2}}} = a^{n} \sin^{- 1} (\frac{x}{a} - 1)$ . The value of n is
(You may use dimensional analysis to solve the problem.)

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Correct option is A

Trigonometric function has no dimension, so xa= dimensionless Thus, a has the dimensions as x in equation.LHS of given equation is dimensionless and hence, an is dimensionless⇒ n=0

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∫dx2ax−x2=ansin−1⁡xa−1. The value of n is(You may use dimensional analysis to solve the problem.)

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$\int \frac{dx}{\sqrt{2 ax - x^{2}}} = a^{n} \sin^{- 1} (\frac{x}{a} - 1)$ . The value of n is
(You may use dimensional analysis to solve the problem.)