First slide

AC Circuits

Question

A 40 $Ω$ electric heater is connected to a 200 V, 50 Hz mains supply. The peak value of electric current flowing in the circuit is approximately

Moderate

A

2.5 A
B

5.0 A
C

7 A
D

10 A

Solution

$i_{r . m . s .} = \frac{V_{r . m . s .}}{R} = \frac{200}{40} = 5 A \Rightarrow i_{0} = i_{r . m . s .} \sqrt{2} = 7 .07 A$

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