First slide

Alternating current and voltage

Question

A $40 Ω$ electric heater is connected to a 200 V 50 Hz mains supply. The peak value of electric current flowing in the circuit is approximately

Easy

A

2.5 A
B

5.0 A
C

7 A
D

10 A

Solution

$i_{r.m.s.} = \frac{V_{r.m.s.}}{R} = \frac{200}{40} = 5 A \Rightarrow i_{0} = i_{r.m.s.} \sqrt{2} = 7 .07 A$

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