Questions
A 40 F capacitor is a defibrillator is charged to 3000 V The energy stored in the capacitance is sent through the patient during a pulse of duration 3 ms. The power delivered to the patient is
detailed solution
Correct option is B
P=Wt= electrostatic potential energy time ∴P=12CV2t=12×40×10−6×(3000)22×10−3=90×103W=90kW.Talk to our academic expert!
Similar Questions
Two identical capacitors, have the same capacitance C. One of them is charged to potential V1 and the other to V2. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
