Questions
A capacitor is fully charged to a potential difference of 50V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20V. The capacitance of the second capacitor is:
detailed solution
Correct option is A
VCMcommon potential=C1V1+C2V2C1+C2⇒20=10×5010+C2∵For uncharged capacitor, V=0⇒10+C2=25⇒C2=15μFTalk to our academic expert!
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Two metallic charged spheres whose radii are 20 cm and 10 cm respectively, have each 150 micro-coulomb positive charge. The common potential after they are connected by a conducting wire is
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