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Q.

A  16 μF capacitor, initially charged to 5V, is started charging at t=0 by a source at the rate of 40 t μC/s. How long will it take to raise its potential to 10V?

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a

2 s

b

1 s

c

3 s

d

0.2 s

answer is A.

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Detailed Solution

q=CV dqdt=CdVdt 40 t x 10-6=CdVdt 40 t x 10-6dt=16 x10-6dV  on integrating 40t22=16(10-5)=80     t=2s
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