For ground to ground projection range of a projectile is 240 m and its angle of projection is 450. Then equation of its trajectory is

• A

   $20 y =60 x - \frac{x^2}{240}$ 

• B

  $y = x -\frac{x^2}{240}$  $y=\backslash sqrt\{3\}x-\backslash frac\{\{\{x\}^\{2\}\}\}\{120\}$

• C

    30 y =$y=\backslash frac\{x\}\{\backslash sqrt\{3\}\}-\backslash frac\{\{\{x\}^\{2\}\}\}\{480\}$x - $\frac{x^2}{80}$

• D

    y = 30 x - $\frac{x^2}{80}$$\backslash vec\{u\}\backslash ,\backslash ,=\backslash ,\backslash ,\backslash left(\; 20\backslash hat\{i\}+20\backslash sqrt\{3\}\backslash hat\{j\}\; \backslash right)$