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An Intiative by Sri Chaitanya
a
20 y =60 x - x2240
b
y = x -x2240 y=\sqrt{3}x-\frac{{{x}^{2}}}{120}
c
30 y =y=\frac{x}{\sqrt{3}}-\frac{{{x}^{2}}}{480}x - x280
d
y = 30 x - x280\vec{u}\,\,=\,\,\left( 20\hat{i}+20\sqrt{3}\hat{j} \right)
answer is B.
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