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An $α$ - particle collides with a stationary lithium, as $^{4} H e +^{7} L i \to^{10} B + n$ . If Q value of this reaction is $Q = - 2.5 M e V$ . Find the minimum value of kinetic energy of $α$ - particle required for the reaction?

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4.42 MeV

1.52 MeV

2.92 MeV

3.92 MeV

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detailed solution

Correct option is D

Threshold energy =Eth=−Q1+AαALi=−−2.51+47MeV ⇒Eth=3.92MeV

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When a slow moving neutron collides with Uranium 235 atom $(\underset{92}{235} U)$ , following reaction occurs.

$_{0}^{1} n +_{92}^{235} U ⟶_{92}^{236} U^{*} ⟶_{40}^{99} Zr +_{52}^{134} Te + 3_{0}^{1} n$

If kinetic energy of neutrons is neglected (as it is very small), then the Q of reaction is 37 x K MeV. The value of K is _________. Use following data.

$m (U^{235}) = 235.0439 u, m (n) = 1.0087 u,$

$m (Z r^{99}) = 98.9165 u, m (T e^{134}) = 133.9115 u .$

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An α - particle collides with a stationary lithium, as 4He+7Li→10B+n . If Q value of this reaction is Q=−2.5MeV. Find the minimum value of kinetic energy of α- particle required for the reaction?

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Ready to Test Your Skills?

free study material

An $α$ - particle collides with a stationary lithium, as $^{4} H e +^{7} L i \to^{10} B + n$ . If Q value of this reaction is $Q = - 2.5 M e V$ . Find the minimum value of kinetic energy of $α$ - particle required for the reaction?