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An -particle of 7 MeV energy strikes with a nucleus of uranium at stationary at an scattering angle of . The nearest distance upto which -particle reaches the nucleus will be of the order of
detailed solution
Correct option is C
At closest distance of approach Kinetic energy = Potential energy ⇒7×106×1.6×10−19=14πε0×(ze)(2e)rFor uranium z= 92, so r=5.3×10−12cmTalk to our academic expert!
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