First slide

Scattering of a-particles and Rutherford’s nuclear Model of Atoms.

Question

An $α$ -particle of 7 MeV energy strikes with a nucleus of uranium at stationary at an scattering angle of $180^{o}$ . The nearest distance upto which $α$ -particle reaches the nucleus will be of the order of

Easy

A

1 Å
B

$10^{- 10} cm$
C

$10^{- 12} cm$
D

$10^{- 15} cm$

Solution

At closest distance of approach
Kinetic energy = Potential energy
$\Rightarrow 7 \times 10^{6} \times 1 .6 \times 10^{- 19} = \frac{1}{4 {πε}_{0}} \times \frac{(ze) (2 e)}{r}$
For uranium z= 92, so $r = 5 .3 \times 10^{- 12} cm$

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