Questions
A particle is moving along a straight line PQR with constant acceleration. It crosses the point P with a velocity of 5 m/s and the point R with a velocity of 25 m/s. If QR = 2(PQ), find the velocity with which if crosses the point Q
a
b
c
d
detailed solution
Correct option is C
v2 =52 + 2PQ a .............1 and 252 =v2 +22×PQ a ..............2 Solving , v =15m/sTalk to our academic expert!
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A particle moving along a straight line has a velocity vms-1, when it has cleared a distance y meter. These two are connected by the relation . When its velocity is 1ms-1, its acceleration(in ms-2) is
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