Questions
A particle starts from origin with a velocity of 10 m/s and continues to move along positive x-axis with uniform retardation of 5 m/s2. Then length of path traversed by the particle when it cross the origin again is
a
b
c
d
detailed solution
Correct option is B
When the particle stops momentarily , its displacement x = 1022×5 m = 10 mTherefore length of path traversed = 2×10 m =20 mTalk to our academic expert!
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The displacement of a particle moving in a straight line is described by the relation S=6+12t-2t2. Here s in meter and t is in sec. The distance covered by the particle in first 5s is
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