First slide

Radio activity

Question

An $α -$ particle strikes an aluminium atom $_{13}^{27} A l$ . As a result, an unknown nucleus $_{Z}^{A} X$ and a neutron are formed. Then values of A and Z are respectively

Easy

A

31 and 14
B

32 and 13
C

30 and 15
D

28 and 17

Solution

$_{13}^{27} A l +_{2}^{4} H e \to_{Z}^{A} X +_{0}^{1} n$
$\begin{array}{l} ∴ 27 + 4 = A + 1 \Rightarrow A = 30 \\ and 13 + 2 = Z \Rightarrow Z = 15 \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App