An α$$-particle$$ travels in a circular path of radius $$0.45$$ m in a magnetic field B $$=$$ $$1.2$$ $$Wb/m2$$ with a speed of $$2.6$$×$$107$$ $$m/s$$. The period of revolution of the α$$-particle$$

Correct option is 31.1×10−7 s

Questions

An $α -particle$ travels in a circular path of radius 0.45 m in a magnetic field B = 1.2 Wb/m² with a speed of $2.6 \times 10^{7} m / s$ . The period of revolution of the $α -particle$

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detailed solution

Correct option is C

T=2πmqB=2πrv=2×3.14×0.452.6×107=1.08×10−7 s

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An α-particle travels in a circular path of radius 0.45 m in a magnetic field B = 1.2 Wb/m2 with a speed of 2.6×107 m/s. The period of revolution of the α-particle

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An $α -particle$ travels in a circular path of radius 0.45 m in a magnetic field B = 1.2 Wb/m² with a speed of $2.6 \times 10^{7} m / s$ . The period of revolution of the $α -particle$