First slide

Alternating current and voltage

Question

A $10 Ω$ resistor is carrying a current $i = (3 + 4 \sqrt{2} \sin 100 πt) A$ then potential difference between the ends of the resistor measured by an a.c. ammeter is

Moderate

A

30 volt
B

40 volt
C

50 volt
D

60 volt

Solution

$I_{rms} = \sqrt{3^{2} + \frac{{(4 \sqrt{2})}^{2}}{2}} A = 5 A$
$∴$ Potential difference $= I_{rms} . R = 5 \times 10 volt = 50 volt$

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