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Questions  

10 Ω resistor is carrying a current i=3+42sin100πtA then potential difference between the ends of the resistor measured by an a.c. ammeter is

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a
30 volt
b
40 volt
c
50 volt
d
60 volt

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detailed solution

Correct option is C

Irms=32+4222A=5A∴ Potential difference =Irms.R=5×10 volt=50 volt

ctaimg

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