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$\int_{0}^{1} (t^{2} + 9 t + c) d t = \frac{9}{2}$ Find the value of 'c'

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Correct option is A

=∫01 t2+9t+cdt=92=t33+92t2+ct01=92=13+92+c=92⇒c=−13

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∫01 t2+9t+cdt=92Find the value of 'c'

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$\int_{0}^{1} (t^{2} + 9 t + c) d t = \frac{9}{2}$ Find the value of 'c'