First slide

Projection Under uniform Acceleration

Question

When a body is projected horizontally from a point on an inclined plane having inclination 300 with horizontal, maximum height attained by it is found to be 20 m. When the same body is projected with same speed from a point on the same inclined plane in a direction perpendicular to the plane maximum height attained by the body with respect to the inclined plane will be

Moderate

A
80 m
B
60 m
C
26.67 m
D
32.33 m

Solution

$F o r h o r i z o n t a l p r o j e c t i o n, \frac{u^{2} \sin^{2} 30^{0}}{2 \times 10 \times \cos 30^{0}} = 20 \Rightarrow u^{2} = 800 \sqrt{3} m^{2} / s^{2}$
$F o r p r o j e c t i o n n o r m a l t o t h e i n c l i n e d p l a n e, H_{m a x} = \frac{u^{2}}{2 g \cos β} = \frac{800 \sqrt{3}}{2 \times 10 \times \cos 30^{0}} m \Rightarrow H_{m a x} = 80 m$

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