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$\int_{0}^{1} \frac{x - 1}{x^{2} - 1} d x$

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ℓn⁡(2)

ℓn(6) – ℓn(3)

ℓn(3) – ℓn(6)

– ℓn(2)

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detailed solution

Correct option is A

∫01 x−1x2−1=∫01 x−1(x+1)(x−1)=∫01 1(x+1)dx=ℓn(x+1)01=ℓn2

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∫01 x−1x2−1dx

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$\int_{0}^{1} \frac{x - 1}{x^{2} - 1} d x$