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A 1 µA beam of protons with a cross-sectional area of 0.5 sq. mm is moving with a velocity of $3 x 10^{4} {ms}^{- 1}$ . Then charge density of beam is

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6.6 x 10-4 C / m3

6.6 x 10-5 C / m3

6.6 x 10-6 C / m3

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detailed solution

Correct option is B

For one second, distance = Velocity = 3×10−4m/secand Q=i×1=10−6C. Charge density=ChargeVolume10−63×104×0.5×10−6=6.6×10−5C/m3.

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A 1 µA beam of protons with a cross-sectional area of 0.5 sq. mm is moving with a velocity of 3 x 104 ms-1. Then charge density of beam is

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Ready to Test Your Skills?

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A 1 µA beam of protons with a cross-sectional area of 0.5 sq. mm is moving with a velocity of $3 x 10^{4} {ms}^{- 1}$ . Then charge density of beam is