A220 V 50 Hz AC generator is connected to an inductor and a 50 Ω resistance in series. The current in the circuit is 1.0 A. What is the potential difference across inductor?
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a
102.2 V
b
186.4 V
c
214.24 V
d
302 V
answer is C.
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Detailed Solution
I=EZ⇒1=220Z⇒Z=220 ΩVR=50×1 Volt Now V2=VR2+VL2⇒VL=2202-502 volt=214.24 volt