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Q.

A220 V 50 Hz AC generator is connected to an inductor and a 50 Ω resistance in series. The current in the circuit is 1.0 A. What is the potential difference across inductor?

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a

102.2 V

b

186.4 V

c

214.24 V

d

302 V

answer is C.

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Detailed Solution

I=EZ⇒1=220Z⇒Z=220 ΩVR=50×1 Volt Now V2=VR2+VL2⇒VL=2202-502 volt=214.24 volt
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