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AB is a thin rod of length l. Its moment of inertia about axis (1) isI1 and that about axis (2) is I2. If I1 > I2, and c be the position of centre of mass of the rod, then

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answer is 3.

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Detailed Solution

By parallel axis Theorem,I1=IC+mAC2I2=IC+mBC2Since, I1>I2,  we conclude   AC > BC.Also AC + BC = l.∴     AC  >  l2.
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