First slide

Electrostatic force

Question

ABC is a right angle triangle with sides AB=3 cm BC=4 cm and AC=5 cm . Charges +15, +12 and -20 esu are placed at A,B,C respectively. Magnitude of force experienced by the charge at B in dyne is

Moderate

Solution

$F_{B A} = k \frac{q_{A} q_{B}}{r_{A B}^{2}} = (1) \frac{15 \times 12}{{(3)}^{2}} = 20 d y n e a l o n g \vec{A B} F_{B C} = k \frac{q_{B} q_{C}}{r_{B C}^{2}} = (1) \frac{12 \times (- 20)}{{(4)}^{2}} = 15 d y n e a l o n g \vec{B C} F_{B} = \sqrt{F_{B A}^{2} + F_{B C}^{2}} = \sqrt{{(20)}^{2} + {(- 15)}^{2}} = \sqrt{625} = 25 d y n e$

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